Question 1

Question 1a to 1d - multiple choice question

a	\(2\dfrac{1}{2}×1\dfrac{1}{4}=\)
	2	2\(\dfrac{1}{8}\)	3\(\dfrac{1}{8}\)
b	\(1\dfrac{1}{8}÷7\dfrac{1}{2}=\)
	\(\dfrac{3}{20}\)	\(\dfrac{20}{3}\)	\(8\dfrac{7}{16}\)
c	\(2\dfrac{1}{9}÷2\dfrac{1}{4}=\)
	\(\dfrac{76}{81}\)	4\(\dfrac{3}{4}\)	4\(\dfrac{1}{36}\)
d	\(5\dfrac{1}{2}÷7\dfrac{1}{3}=\)
	\(\dfrac{3}{4}\)	1\(\dfrac{1}{3}\)	1\(\dfrac{1}{21}\)

Question 2

In a box of chocolates, \(\dfrac{3}{5}\) of the chocolates have soft centres. The remainder have hard centres. The fraction that have hard centres is:

Numerator — Denominator

Question 3

Justin made 200 meat pies. He sold \(\dfrac{2}{5}\) of them and gave \(\dfrac{1}{4}\) of the remainder to a friend. The number of pies he has left is:

Question 3 - multiple choice question

40

90

120