Identifying a possible non-linear rule for a given table of values
Identifying a possible non-linear rule for a given table of values
Solution (substitution)
When x = 0, y = 1
One method of finding the correct answer is to try each of the options with a value of x. If an option does not give the correct y value it cannot be a correct response to the question.
The constant term is 1 which is the case for all the alternatives.
Option 1: |
y = 1 − 2x² |
When x = −1 | |
y = 1 − 2 × (−1)² = 1 − 2 = −1 ≠ 3 | |
Option 2: |
y = 2x + 1 |
When x = −1 | |
y = 2 × −1 + 1 = −2 + 1 = −1 ≠ 3 | |
Option 3: |
y = 2x² + 1 |
y = 2 × (−1)² + 1 = 3, y = 2 × (−2)² + 1 = 9, y = 2 × (−3)² + 1 = 19 | |
Only one of the options is possible. |
The answer is y = 2x² + 1.
Note: Using this method it might be necessary to try other values of x. It assumes that there is only one correct solution.
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