Solving problems with percentages
Percentage increase
Question 5
Mira made this table showing population data over 2 years for the 6 Australian states.
Some data for South Australia is not shown.
Population of Australian states | |||
---|---|---|---|
2002 |
2003 population |
Percentage increase from previous year | |
NSW | 6 662 212 | 6 716 277 | 0.8% |
Vic | 4 884 952 | 4 947 985 | 1.3% |
Qld | 3 754 154 | 3 840 111 | 2.3% |
SA | 1 522 475 | ? | 0.6% |
WA | 1 936 902 | 1 969 046 | 1.7% |
Tas | 474 305 | 479 958 | 1.2% |
What was the population of South Australia (SA) closest to in 2003?
- a
- 2 537 500
- b
- 2 436 000
- c
- 1 613 800
- d
- 1 531 600
Solution
Method 1: by hand
0.6% of 1 522 475 | = \(\dfrac{0.6}{100}\) × 1 522 475 |
= \(\dfrac{6}{1000}\) × 1 522 475 | |
= \(\dfrac{9134850}{1000}\) | |
= 9134.85 |
Population in 2003 = 1 522 475 + 9134.85 = 1 531 609.85
Method 2: by hand
The 2003 population | = 1 522 475 + 0.6% of 1 522 475 |
= 1 522 475 (1 + 0.6%) | |
= 1 522 475 × 1.006 |
Method 3: By calculator
1.006 × 1 522 475 = 1 531 609.85
The answer is d 1 531 600.
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